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0.25x^2-6x+15=0
a = 0.25; b = -6; c = +15;
Δ = b2-4ac
Δ = -62-4·0.25·15
Δ = 21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-\sqrt{21}}{2*0.25}=\frac{6-\sqrt{21}}{0.5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+\sqrt{21}}{2*0.25}=\frac{6+\sqrt{21}}{0.5} $
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